केवटराज की ऩ
ु
त्री का नाम क्या था?
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According to the question by using the formula we get,
\longrightarrow \sf 90 =\: 50 + a(0.005)⟶90=50+a(0.005)
\longrightarrow \sf 90 =\: 50 + 0.005a⟶90=50+0.005a
\longrightarrow \sf 90 - 50 =\: 0.005a⟶90−50=0.005a
\longrightarrow \sf 40 =\: 0.005a⟶40=0.005a
\longrightarrow \sf \dfrac{40}{0.005} =\: a⟶
0.005
40
=a
\longrightarrow \sf 8000 =\: a⟶8000=a
\longrightarrow \sf\bold{\red{a =\: 8000\: km/h^2}}⟶a=8000km/h
2
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