Question

kahalil varg samikaran purn bath padhatine sodva x2-3x-1=0​

Answer 1

Answer:

comparing the above with

$a {x}^{2} + bx + c = 0$

then,

a=1 b=-3 and c=-1

by formula method,

X=-b+- √b^2-4ac/2a

X=-(-3)+-(√(9-4×1(-1))/2

X=-3+-(√9+4)/2

x=-3+-(√13)/2