Question

Kalief's scores on his first four History tests were 90, 85, 88, and 95. To get an A in the class, he needs to have an average of 90 or better. What score must he make on the fifth test to get an A?

Answer 1

Answer:

the score on 5th test is

=5×90-(90+85+88+95)

=450-358

=92

Answer 2

Answer:

92 marks

Step-by-step explanation:

Sum of marks of the the first 4 exams = 90+85+88+95 = 358

Marks to be scored to get an A grade = 90% of 500 ( 5 exams of 100 marks each) = 450

Hence marks required in last exam = 90+85+88+95+x=450

358+x=450

x=450-358

x=92