Kamal wrote a two digit number whose units place the digit is X and the digit in tens place is 9. If the number is 16times the digit in unit's place, find the number.
This is a sum from the chapter Equation.
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Step-by-step explanation:
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 9-x
\because 2-digit number = 10 x tens place digit + unit place digit
\therefore Original number = 10(9-x)+x
According to the question, New number
= Original number + 27
\Rightarrow10x+\left(9-x\right)=10\left(9-x\right)+x+27
\Rightarrow10+9-x=90-10x+x+27
\Rightarrow9x+9=117-9x
\Rightarrow9x+9x=117-9
\Rightarrow18x=108
\Rightarrow x=\frac{108}{18}=6
Hence, the 2-digit number = 10(9-x)+x = 10(9-6)+6 = 10 x 3 + 6 = 30 + 6 = 36
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