Question

Kanchan spend 1/2 of her money in one shop .she spend 1/3 of what was left with her on rickshaw fare .at the end ,she has rs 20 with her . how much did she have in the beginning?

Answer 1

HEY DEAR ...

Let Kanchan have Rs X with her in the beginning.

     Then   Rs X/2 she is left with after shopping.
        Afterwards 1/3 of (X/2) is spent on rickshaw.
           So (1 - 1/3) rd of (X/2) is what she is left with.

     (2/3) * X/2 is left with her after rickshaw fare. 
            =>   X/3 = Rs 20
 
     So  she had  Rs 60. with her in the beginning.

HOPE , IT HELPS ...

Answer 2

Let's say Kanchan had x rupees. Then she spent $\frac{1}{2} x$ rupees in a shop. That means she had $\frac{1}{2} x$ rupees left. That means she spent $\frac{1}{2}x$×$\frac{1}{3} =\frac{1}{6}x$ rupees in Rickshaw Fare.

So, she spent $\frac{1}{2}x$ rupees in one place and $\frac{1}{6} x$ in the other and had 20 rupees left after that. We can write this as a following equation:

$x-\frac{1}{2}x -\frac{1}{6}x=20$. Simplifying the left side, we get $\frac{1}{3}x =20$, and multiplying both sides by three, we get $x=60$. So, Kanchan had 60 rupees in the beginning.