Question

Kangaroo can jump 2.5 m vertically. What must be the initial velocity of the kangaroo?

Answer 1

Hello friend

Here is your answer

____________________________

Given :

Acceleration (a) = 9.8 m/s^2 .....(due to gravity)

Displacement (s) = 2.5 m

Velocity (v) = 0

We have to find out:

Initial velocity (u) = ??

So, we know that

v^2 = u^2 + 2as

0^2 = u^2 + 2 x (-9.8) (2.5) .......

.( The negative sign is used as the acceleration is in the opposite direction of the Velocity)

0 = u^2 - 49

u^2 = 49

u = 7 m/s.

Therefore, the initial velocity of the kangaroo must be 7 m/s.


Thanks...... :)

Answer 2

Answer:

The initial velocity of the kangaroo must be 7 m/s.

Explanation:

a = 9.8 m/s²

s = 2.5 m

v = 0 m/s

v² = u² + 2as

=> (0)² = u² + 2 * (-9.8) * 2.5

=> 0 = u² - 5 * 9.8

=> 0 = u² - 49

=> u² = 0 + 49

=> u² = 49

=> u = 7 m/s

So,

The initial velocity of the kangaroo must be 7 m/s.

Here, negative sign of acceleration shows that it is in the opposite direction of the velocity.