Question

kantabai bought 1 1/2 kg of tea and 5 kg of sugar from a shop. she paid 50rs as return fare for ricshaw. the total expense was 700rs. then she realised by ordering online the goods can be brought with free home delivery at the same price. so next month she placed an order online for 2 kg tea and 7kg sugar. she paid 880rs for that. find the cost of tea and sugar per kg.

Answer 1

hey can you explain it briefly

Answer 2

ANSWER

Find out the cost of tea and sugar per kg.

To proof

Let us assume that the cost of tea = x

Let us assume that the cost of sugar = y

As given

1 1/2 kg of tea and 5 kg of sugar from a shop. she paid 50rs as return fare for ricshaw.

total expense was 700rs

than the equation becomes

$\frac{11x}{2} + 5y + 50 = 700$

simply written as

11x +10y +100 =1400

11x +10y = 1300

As given

she placed an order online for 2 kg tea and 7kg sugar.

she paid 880rs

than the equation becomes

2x +  7y = 880

than the two equation becomes

11x +10y = 1300 and 2x +  7y = 880

multiply 11x +10y = 1300 by 2 and 2x +  7y = 880 by 11

we get

22x + 20 y =2600

22x + 77y =9680

subtracted 22x + 20 y =2600 from 22x + 77y =9680

57y = 7080

$y = \frac{7080}{57}$

y = Rs 124.2 (approx)  

put in the equation

2x +  7y = 880

2x + 869.4 = 880

2x = 10.6

x = Rs 5.3

cost of tea =Rs 5.3

cost of sugar =Rs124.2

Hence proved