Question

Kantabai bought 11/2 kg tea and 5 kg sugar from a shop. She paid rupees 50 as return fare for rickshaw. Total expense was rupees 700. Then she realised that by ordering online the goods can be bought with free home delivery at the same price. So next month she placed the order online for 2 kg tea and 7 kg sugar. She paid rupees 880 for that. Find the rate of sugar and tea per kg. Solve the word problem

Answer 1

Let, rate of 1 kg. Tea be Rs.x and rate of 1 kg. Sugar be Rs. y
 ∴ According to First condition,
1 1/2x  + 5y  + 50 = 700
∴ 3/2x + 5y = 700 -50
∴ 3/2x + 5y = 650
∴ 3x + 10y = 1300......Multiply by 2.......(1)
According to Second condition,
2x + 7y = 880 ..........(2)
Multiply equation (1) by 2
∴ 6x + 20y = 2600.........(3)
Multiply equation (2) by 3
∴ 6x + 21y = 2640.........(4)
Subtract equation (3) from (4)
∴6x +21y = 2640
- 6x +20y = 2600
∴ 0 + y     = 40
∴ y = 40........(5)
Substitute the value of y from equation (5) in equation (2)
2x + 7y = 880
∴ 2x + 7× 40 = 880
∴ 2x + 280 = 880
∴ 2x = 880 - 280
∴ 2x = 600
∴ x = 600/2
∴ x = 300
∴ x = Rs. 300
∴ Rate of Tea = x = Rs.300
∴ Rate of Sugar = y = Rs.40

Answer 2

Answer:

Step-by-step explanation: