Question

Kanti bottle laptop for Rs 24000 and sold it to Ishwar a gain of 15% Ishwar sold it to Shekar at 10% loss find the selling price of Ishwar

Answer 1

Given, CP of laptop for Kanti = Rs 24000
Gain% for Kanti = 15%
Loss% for Ishwar = 10%

SP of laptop for Kanti = CP of laptop for ishwar = CP for Kanti+15% of CP for Kanti
                                                                            =24000 + 15% of 24000
                                                                            = 24000 + $\frac{15}{ 100}$ * 24000
                                                                            = 24000 +3600
                                                                            = 27600

SP of laptop  for Ishwar = CP of laptop for Shekar= CP for Ishwar -10% of CP for Ishwar
                                                                                = 27600 - $\frac{10}{100}$ * 27600
                                                                                =27600-2760
                                                                                =24840

Hence, SP of laptop  for Ishwar = Rs 24840

Answer 2

Solution :-

Cost Price of the laptop for Kanti = Rs. 24000

Profit earned = 15 %

Selling Price of the laptop for Kanti = 24000 + (24000*15)/100

⇒ 24000 + 3600

= Rs. 27600

Selling Price of the laptop for Kanti = 27600

Selling Price for Kanti = Cost Price for Ishwar

Cost Price of the laptop for Ishwar = Rs.27600

Loss incurred to Ishwar on selling = 10 %

Selling Price of laptop for Ishwar = 27600 - (27600*10)/100

⇒ 27600 - 2760 

= Rs. 24840

So, Selling Price of laptop for Ishwar is Rs. 24840.

Answer.