Question

Kapil drives 12 km towards west and 3 km south he then turns east and drives 8 kms how far he from his starting point

Answer 1

Answer:

Kapil is 5km away from the starting point.

Step-by-step explanation:

Here AB = 12 km, BC = 3 km, CD = 8km

We have  to find AD.

(Please refer attachment.)

We have obtained a right trapezoid and have to calculate one of its sides.

(The green lines are the extensions to solve the problem)

Now, AE = BC = 3

and DE = AB - CD = 12-8 = 4

Applying Pythagoras theorem to ΔAED, which states,

hypotenuse² = base²+perpendicular²

we have

AD² = AE² + DE²

      = 3² + 4² =9 +16 =25

AD = √25 =5

∴ Kapil is 5km away from the starting point.

Answer 2

Concept:

Pythagoras theorem:

Hypotenuse² = Base² + Perpendicular²

Given:

Kapil drives:

12 km towards west and 3 km south he then turns east and drives 8 km.

Find:

Distance from the starting point.

Solution:

From the figure, we get that:

AB = 12 km, BC = 3 km, CD = 8km

We need to find AD.

Now, AE = BC = 3 km

and

DE = AB - CD = 12 - 8 = 4 km

Applying Pythagoras theorem to ΔAED:

AD² = AE² + DE²

= 3² + 4²

= 9 + 16 = 25

AD = √25 = 5 km

Therefore, Kapil is 5 km away from the starting point.

#SPJ2