Question

Karan is 2 year older to teja now. After 4 years, their ages will be in the ratio of 11:10 . Find their present ages.

Answer 1

$\textbf{Given:}$

$\text{Karan is 2 year older to teja now}$

$\text{After 4 years, their ages will be in the ratio of 11:10 }$

$\textbf{To find:}$

$\text{Present ages of Karan and Teja}$

$\textbf{Solution:}$

$\text{Let the present ages of Karan and Teja be x and y with x>y}$

$\text{As per given data,}$

$x=y+2$......(1)

$\text{After 4 years, their ages are in the ratio 11:10}$

$\implies\,x+4:y+4=11:10$

$\implies\dfrac{x+4}{y+4}=\dfrac{11}{10}$

$\text{Using (1), we get}$

$\implies\dfrac{(y+2)+4}{y+4}=\dfrac{11}{10}$

$\implies\dfrac{y+6}{y+4}=\dfrac{11}{10}$

$\implies\,10y+60=11y+44$

$\implies\,11y-10y=60-44$

$\implies\bf\,y=16$

$(1)\implies\bf\,x=18$

$\therefore\textbf{The present ages of Karan and Teja are 18 and 16 respetively}$

Find more:

The average age of a family of 5 members is 21 years. if the age of the youngest member is 5 years then the average age of the family at the birth of the youngest member was

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Answer 2

Answer:

present ages of Karan and teja:

karan = x+2

teja = x

Given ratio after 4 years is 11/10

Age after 4 years :

karan = (x+2)+4

teja = (x)+4

------>

(x+2)+4/x+4 = 11/10

10(x+6) = 11(x+4)

10x +60 =11x+44

60 - 44 = 11x -10x

16 = x

Therefore present ages of karan and teja :

karan = (x+2) = > since x= 16 => 16+2 = 18

Teja = x  => 16