Question

Kartik and Pravin start cycling from some
point A. Kartik travels due east and Pravin
travels due north. After 1 hour, Pravin covers
12 km and Kartik travels 5 km. How far are
they from each other?​

Answer 1

Answer:

They are 13 KM apart

Step-by-step explanation:

The pythagorean theorem will be used to determine the distance between them. Kartik walk east 5 km and Parvin walks north, so they will create a right angled triangle. Using the pythagorean theorem:

Distance = $\sqrt{12^{2} +5^2}$

= $\sqrt{169}$

= 13 Km

Answer 2

The correct answer is 13 km.

Given: Distance travelled by Pravin and Kartik are 12 km and 5 km respectively.

To Find: How far they are after 1 hour.

Solution:

Kartik travels due east and Pravin due north.

So, this forms a right angled triangle.

Right angled at the place from where they started to move.

Base = Kartik's distance from starting point.

Height = Pravin's distance from starting point.

Hypotenuse = How far they will be after 1 hour.

So,

$Hypotenuse^{2} =Base^{2} +Height^{2}$

= $12^{2}+5^{2}$

= 169

Hypotenuse = 13

Hence, the distance between Kartik and Pravin after 1 hour is 13 km.

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