Math, asked by Abhaytyagi, 1 year ago

kartik is younger than som by 12 years. If 6 years ago, ratio of their ages was 3:5, find the ratio of their ages after 6 years from now.

Answers

Answered by ranirinkulaltu
8

answer 5:7

Step-by-step explanation:

Let Som's age be x,

Kartik's be x-12

6 years ago,

Som's age x-6

Kartik's age x-12-6

ATP,

x-18/x-6=3/5

5x-90=3x-18

2x=72

x=36

6years from now,

Som's age will be 36+6=42

Kartik's age will be 42-12=30.

Ratio of their ages,

30:42

5:7

Answered by sourasghotekar123
3

Answer:

Kartik is younger than som by 12 years. If 6 years ago, ratio of their ages was 3:5, find the ratio of their ages after 6 years from now.

Step-by-step explanation:

  • We are given that- there are two boys- Kartik and Som.
  • Kartik is younger than Som by 12 years. Six years ago the ration of there ages was 3: 5.
  • And we have to find- the ratio of there ages after 6 years from now.
  • Let the age of Som be x.

Therefore, the age of Kartik will be x-12,

six years ago,

The age of Som was-x-6 and

The age of Kartik is x-12-6

At present,

\frac{x-18}{x-6}= \frac{3}{5}

By solving this equations-5 \times (x-18)= 3 \times(x-6)\\5x-90= 3x-18\\2x=72\\x=\frac{72}{2}\\ x= 36

6 years from now,

Som's age will be 36+6= 42\\

Kartik's age will be 42-12= 30

So the ratio of there ages will be 30:42

That is, 5:7

Hence, the ratio of ages of kartik and som after 6 years from now is 5:7.

#SPJ3

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