Question

kashvi weighs 36 kg. She is standing on the ground . If area of either foot of kashvi is 150cm² then calculate the pressure exerted by her on the ground . Take g = 10m/s²​

Answer 1

Question :

A girl weighs 36 kg. She is standing on the ground . If area of either foot of kashvi is 150 cm ² , then calculate the pressure exerted by her on the ground.

Take g = 10 m/s ²

Answer :

Mass of girl = 36 kg .

g = 10 m/s²

Area of her either feet = 150 cm² = 150×10^-4 m²

Thrust , F = weight of the girl.

= mg = 36×10 = 360 N

Total area of her both feet = 2A = 2(150×10^-4) = 3×10 ^2 m²

Pressure = Thrust / Area = 360/3×10^-2 = 1.2×10⁴ Pa

So , the required pressure is = 1.2×10^-4 Pa .

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Answer 2

Answer:

1.2×10⁴ Pa

Explanation:

here,

mass of the girl m=36kg

g(gravity)=10 ms²

A(area)=150 cm²

F(thrust)=weight of the girl

=mg=36×10=360N

total area of both feet =2A=2×150×10⁴ m²=3×10²m²

P=thrust/area

=360/3×10²=1.2×10⁴Pa