Kavya plants 4 saplings in a row in her garden. The distance between two adjacent saplings is 3/4 m. Find the distance between the first and the last sapling.
Answers
Answered by
0
Answer:
3/4+3/4+3/4 = 2.25 metre distance
Step-by-step explanation:
1 ---------3/4 -------. 2 -------3/4--------. 3--------3/4-----4 then 3, 3/4 so add them
Answered by
1
Answer:
As there are 4 saplings and distance between two adjacent saplings is 34 m, Distance between first and last sapling =3∗34=94=214m.
Step-by-step explanation:
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