Math, asked by yashitaphate77, 17 days ago

Kavya's mother is 3 and half times as old as Kavya. after 2 years Kavya's Mother will be three times as old as she will be then, find their present ages

Answers

Answered by y2krahulsingh
2

Answer:

Let Kavya's present age be x years

Therefore,

Kavya's mother present age

= (3 whole 1/2 × x) years

= 7/2 × x years

= 7x/2 years

A.T.Q,

7x/2 + 2 = 3 (x+2)

or, (7x×1 + 2×2) / 2 = 3×x + 3×2

or, (7x + 4) / 2 = 3x + 6

or, 7x + 4 = 2 (3x + 6)

or, 7x + 4 = 2×3x + 2×6

or, 7x + 4 = 6x + 12

or, 7x - 6x = 12 - 4

or, x = 8

Answer :- Kavya's present age = x = 8 years

kavya's mother present age = 7x/2 years

= 7×8/2 years

= 7 × 4 years

= 28 years

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