Question

KC for PCL5 + gives pcl3 + cl2 is 0.04 at the 25 degree Celsius how many moles of PCL5 must be added to a 3 litre flask to obtain a cl2 concentration of 0.15 m

Answer 1

Hey dear,

● Answer- 0.7125 mol

● Explanation-
The reaction occurs as follows-
Reaction PCl5 ---> PCl3 + Cl2
Initial moles n 0 0
Moles at eqlb. n-x x x

We want to obtain,
x = 0.15 mol

Equilibrium constant is given by-
Kc = [PCl3][Cl2] / [PCl5]
Kc = x × x / (n-x)
0.04 = 0.15×0.15 / (n-0.15)
n-0.15 = 0.5625
n = 0.7125 mol

Therefore, 0.7125 mol of PCl5 will be required to get 0.15 mol conc. of Cl2.

Hope this is useful...

Answer 2

Answer:

15.63

Explanation:

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