Question

Kc for the reaction at
equilibrium A+2B = 2C the
value of equilibrium constant K
is 10. What is the value of
equilibrium constant if the
following reaction is reversed?
2 A+4B 4C​

Answer 1

Answer:

Explanation:

A+2B⇌2C, .....(i) K=40

and for C⇌B+  

2

1

​  

A, ......(i) K  

1

​  

=?

K=  

root K

​  

 

1

​  

=  

(40)  

1/2

 

1

​  

 

Since equation (2) is obtained by reversing and dividing by 2, the equation (1)