Question

Kenitic energy of an object of mass ,m moving with a velocity of 5m/s is 25J. What will be the kenitic energy when its velocity is double? What will be it's kenitic energy when its velocity is increased three times ?

Answer 1

$k.e = 25j \\ so \\ 25 = \frac{1}{2} \times m \times (5) {}^{2} \\ therefore \: \\ m = 2kg \\ \: when \: velocity \: is \: doubled \: velocity \: becomes \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 5 = 10ms {}^{ - 1} \\ so \\ k.e = \frac{1}{2} \times 2 \times (10) {}^{2} = 100j \\ when \: velocity \: is \: increased \: 3 \: times \: velocity \: will \: be \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 \times 5 = 15ms {}^{ - 1} \\ k.e = \frac{1}{2} \times 2 \times (15) {}^{2} = 225j$

Answer 2

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ANSWER :

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The mass of the object, m = m kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × m × 25

m = 2 kg

(i) Now the Velocity of the object is doubled,,

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

(ii) Now the velocity is tripled ,,

v3 = 3v1

= 3 ( 5)

v3 = 15 m/s

Kinetic energy, K.E = 1/2 × m × (v3)^2

= 1/2 × 2 × (15)^2

= 225 J

The kinetic energy is 225 J

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