Question

kevin's present age is one -third his mother's present age. if the mother's was five times his age 6 years ago what are their present ages?

Answer 1

kevin's mother age is x
kevin age isx/3
6 years ago
kevin age is x/3-6
kevin mother age =x-6
kevin mother age=5(x/3-6)
x-6=(x-18)/3 *5
3x-18=5x-90
5x-3x=90-18
2x=72
x=36
their present ages of kevin =12
present ages of kevin mother=36

Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\green{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\sf{\pink{Given\::}}}}}$

Kevin's present age is one - third his mother's present age. If the mother's age was five times his age 6 years ago.

$\bf{\Large{\underline{\sf{\red{To\:find\::}}}}}$

Their present ages.

$\bf{\Large{\underline{\sf{\blue{Explanation\::}}}}}$

Let the age of kevin's mother be R

Let the age of Kevin's be $\bf{\frac{1}{3} R}$

• $\bf{\Large{\underline{\bf{\orange{Six\:years\:Ago\::}}}}}$

Kevin's mother age is (R - 6) years

Kevin's age is ${\frac{1}{3} R-6}years$

According to the question:

→ $\bf{(R-6)=5(\frac{1}{3} R-6)}$

→ $\bf{(R-6)=5(\frac{R-18}{3} )}$

→ $\bf{(R-6)=(\frac{5R-90}{3} )}$

→ 3R - 18 = 5R - 90

→ 3R - 5R = -90 + 18

→ -2R = -72

→ R = $\bf{\cancel{\frac{-72}{-2} }}$

→ R = 36 years

Thus,

The present age of kevin's mother is 36 years.

The resent age of kevin's is $\bf{\cancel{\frac{36}{3}}}$ = 12 years.