Question

KF has NaCl type of structure. The edge length of its unit cell has been found to be 537.6 pm. The distance between K positive F negative is

Answer 1

Answer : The distance between $K^+$ and $F^-$ is, 380.140 pm.

Solution : Given,

Edge length of unit cell = 537.6 pm

Given : KF has NaCl type of structure.

NaCl unit cell has face centered cubic structure. So, KF unit cell has also face centered cubic structure.

The relation between the edge length and inter-ionic distance of face cubic centered unit cell is,

$d=\frac{a}{\sqrt{2}}$

where,

d = inter-ionic distance between the ions

a = edge length of unit cell

Now put the value of 'a' in this relation, we get the distance.

$d=\frac{537.6}{\sqrt{2}}=380.140pm$

Therefore, the distance between $K^+$ and $F^-$ is, 380.140 pm.

Answer 2

Answer:

192

Explanation:

the coreect answerr is 192