Question

Kimi saw 13 animals in the barnyard.
Some were chickens and some were sheep.
Altogether there were 36 legs.
How many chickens and how many sheep did Kimi see?

Answer 1

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Sadie D. asked • 12/13/17

kim saw 13 animals in the barnyard. some were chickens and some were sheep. altogether there were 36 legs. how many chickens and sheep did kim see?

Im 11 and i need help for math help me pls

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Andrew M. answered • 12/13/17

TUTOR New to Wyzant

Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

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Hi Sadie,

Let c = # chickens

Let s = # sheep

There are 13 animals so:

c + s = 13

chickens have 2 legs, sheep have 4 and there are 36 legs so:

2c + 4s = 36

We can factor out a 2 here since all are even numbers:

2(c+2s) = 2(18)

c + 2s = 18

You now hqve two equations:

c + s = 13

c + 2s = 18

subtract first equation from the second

c + 2s = 18

-(c + s = 13)

---------------------

s = 5

since c + s = 13

c + 5 = 13

c = 8

He saw 5 sheep and 8 chickens.

Answer 2

Answer:

Let c = # chickens

Let s = # sheep

 There are 13 animals so:

c + s = 13

 chickens have 2 legs, sheep have 4 and there are 36 legs so:

2c + 4s = 36

We can factor out a 2 here since all are even numbers:

2(c+2s) = 2(18)

c + 2s = 18

 You now hqve two equations:

c + s = 13

c + 2s = 18

 subtract first equation from the second

  c + 2s = 18

-(c + s = 13)

---------------------

       s = 5

 since c + s = 13

      c + 5 = 13

      c = 8

 He saw 5 sheep and 8 chickens.