Question

kindly answer soon............​

Answer 1

Answer:

here is u r answer

same model problem here in place

of S place X

hope this answer may helps

Answer 2

Equation:--

$4 {x}^{2} - 4x + 1$

Factorising by splitting middle term(term with power 1)

$4 {x}^{2} - 2x - 2x + 1$

$2x(2x - 1) - 1(2x - 1)$

$(2x - 1)(2x - 1)$

$zeros = \frac{1}{2} = \frac{1}{2}$=α=β

CONFIRMING IT HAS EQUAL ZEROS:---»

D=$\sqrt{ {b}^{2} - 4ac}$

$\sqrt{16 - 4 \times 4 \times 1}$

$\sqrt{0} = 0$

Hence Confirmed

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COEFFICIENT RELATION:---»

1)——»

α+β=$\frac{ - b}{a}$

$\frac{1}{2} + \frac{1}{2} = \frac{ - ( - 4)}{4}$

$1 = 1$

2)——»

αβ=$\frac{c}{a}$

$\frac{1}{ 2} \times \frac{1}{2} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

HENCE VERIFIED

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