Kindly answer the following question without any links or hints. If the roots of the equation 6x 2 - 8√2 x + 4 = 0, are 1] 1/3, √2 2] √2/3, 1 3] √2/3, √2 4] 3/√2,
Answers
Answered by
0
the roots of quad equatio ax2+bx+c is given by
(-b+root(b×b-4×a×c))/(2×a) & (-b-root(b×b-4×a×c))/(2×a)
so roots of 6x2-8root2x+4 are
(8root2+root(128-4×6×4))/12 &
(8root2-root(128-96))/12
(8root2+root(32))/12 &(8root2-root(32))/12
root2&root2/3
ie 3 option
(-b+root(b×b-4×a×c))/(2×a) & (-b-root(b×b-4×a×c))/(2×a)
so roots of 6x2-8root2x+4 are
(8root2+root(128-4×6×4))/12 &
(8root2-root(128-96))/12
(8root2+root(32))/12 &(8root2-root(32))/12
root2&root2/3
ie 3 option
Similar questions