Kindly Answer this question. ( Question 35 )
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An acid A on bromination in the presence of gives two isomers B and C of the formula .
Vigorous oxidation of A, B and C gives acids D, E and F respectively. The acid D, is the strongest acid among all other isomers whereas E and F each has molecular formula of . Give structures of A to F with justification.
Answer:
Refer to the attachment !!
Explanation:
- The acid A has a COOH group due to presence of two oxygen atom and a Br atom.
- As on bromination, it gives two isomeric dibromo derivatives, the two groups in the aromatic acid A must be at the ortho positions.
- Tge compound A on bromination gives two isomers B and C, thus the position of the incoming group should be ortho and para with respect to the Br atom present.
- Since, the corresponding oxidised product D of an aromatic acid (A) is the strongest acid as compared to other isomers, i.e. ortho and para.
- Thus the possible structure of A is : Refer to attachment 1 .
- The reactions involved are : Refer to attachment 2.
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