Question

Kindly explain this in detail.

Answer 1

Given, the mass of the sleds, M = 22.7 kg the mass of the cat, m = 3.63 kg initial velocity of the cat, v = 3.05 m/s We will use the conservation of momentum to get the velocitied of both the sleds So, Momentum when the cat makes her first jump: mv +MV = 0 or, V = -mv/M = (3.63*3.05)/22.7 or, V = -0.488 m/s When the cat jumps on the 2nd sled and come back to the first one, this is quite like an elastic collision So, mv + 0 = -mv + MV1 or, V1 = 2mv/M or, V1.

Answer 2

Answer:

Rudolf Virchow modified the cell theory and give the concept of 'omnis cellula-e cellula' means new cell develop by division of the pre-existing cells

I hope. help you✌️

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