kindly solve it
promise to mark you as brainliest
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Hey!
I think the correct is (4)Tc>Ta
For isothermal expansion,
Ta=Tb
And delta U is zero.
Reversible expansion work done in isothermal expansion is:
-2.303nRTlogV2/V1
Now,
Talking about adiabatic expansion,
Here q=0
That is,
Delta E = q+w
Or delta E = -W (negative because work is done by the system in expansion)
So as internal energy decreases,
That is,
0 in isothermal expansion
And
-ve in adiabatic expansion,
And therefore the temperature of the system should also fall.
That's why,
Tc must be less than Ta.
Hence,
Right answer to your question is,
(4)Tc>Ta.
Thank me later:)
I think the correct is (4)Tc>Ta
For isothermal expansion,
Ta=Tb
And delta U is zero.
Reversible expansion work done in isothermal expansion is:
-2.303nRTlogV2/V1
Now,
Talking about adiabatic expansion,
Here q=0
That is,
Delta E = q+w
Or delta E = -W (negative because work is done by the system in expansion)
So as internal energy decreases,
That is,
0 in isothermal expansion
And
-ve in adiabatic expansion,
And therefore the temperature of the system should also fall.
That's why,
Tc must be less than Ta.
Hence,
Right answer to your question is,
(4)Tc>Ta.
Thank me later:)
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