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area of shaded part = area of greater rec. - area of small rec.
112 = { 12 × 11} - {(11-x) (12-x)}
112 = 132 - { 132-11x-12x+x^2}
-20 = -{ x^2- 23x+132}
20= x^2-23x+132
solve dis and get ur suitable answer
112 = { 12 × 11} - {(11-x) (12-x)}
112 = 132 - { 132-11x-12x+x^2}
-20 = -{ x^2- 23x+132}
20= x^2-23x+132
solve dis and get ur suitable answer
Answered by
1
Given figure is a rectangle.
So, 12 cm = x + a [ let a = remaining part of side parallel to 12 cm side ]
a = 12 - x
Similarly, 11 = x + b [ let b = remaining part of side parallel to 11 cm side]
b = 11 - x
Area of whole rectangle = l * b = 12 × 11 = 132 cm^2
Area of unshaded rectangle = a * b cm^2
= ( 12 - x ) ( 11 - x ) cm^2
Area of shaded portion = 112 cm^2
AREA of shaded portion = Area of whole rectangle - Area of unshaded rectangle
112 = 132 - ( 132 - 12x - 11x +x^2 )
112 = 132 - 132 + 12x +11x - x^2
x^2 - 23x + 112 = 0
X^2 - 16x - 7x + 112 = 0
x ( x - 16 ) - 7 ( x - 16 ) = 0
( x - 7 ) ( x - 16 ) = 0

x is either 7 or 16.
So, 12 cm = x + a [ let a = remaining part of side parallel to 12 cm side ]
a = 12 - x
Similarly, 11 = x + b [ let b = remaining part of side parallel to 11 cm side]
b = 11 - x
Area of whole rectangle = l * b = 12 × 11 = 132 cm^2
Area of unshaded rectangle = a * b cm^2
= ( 12 - x ) ( 11 - x ) cm^2
Area of shaded portion = 112 cm^2
AREA of shaded portion = Area of whole rectangle - Area of unshaded rectangle
112 = 132 - ( 132 - 12x - 11x +x^2 )
112 = 132 - 132 + 12x +11x - x^2
x^2 - 23x + 112 = 0
X^2 - 16x - 7x + 112 = 0
x ( x - 16 ) - 7 ( x - 16 ) = 0
( x - 7 ) ( x - 16 ) = 0
x is either 7 or 16.
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