Question

Kindly solve the following question. Answer only if u know others will be reported.

Answer 1

Step-by-step explanation:

x/m² + y/n² = m-n

=> xn² + ym² = m²n²(m -n) _____________(1)

x/m + y/n = m² -n²

=> xn + ym = mn(m² - n²)

=> xn + ym = mn(m-n) (m+n) ____________(2)

subtracting (1) & (2),

(xn²+ym²)/(xn+ym) = mn/ (m+n)

(xn²+ym²)(m+n) = (xn+ym) mn

xmn²+xn³+ym³+ym²n = xmn²+ym²n

xn³+ym³= 0

xn³= -ym³

x= -ym³/n³ _____________(3)

put eqⁿ (3) in (1) , you will get the value of y

then put the value of in eqⁿ (3), you will get the value of x