Question

kindly solve this...​

Answer 1

Step-by-step explanation:

$\rm \sqrt{\dfrac{\sec θ -1}{\sec θ +1}} + \sqrt{\dfrac{\sec θ+1}{\sec θ -1}}$

$\rm \sqrt{\dfrac{\sec θ -1}{\sec θ +1}× \dfrac{\sec θ -1}{\sec θ -1}} + \sqrt{\dfrac{\sec θ+1}{\sec θ -1}× \dfrac{\sec θ +1}{\sec θ +1}}$

$\sqrt{ \dfrac{(\sec θ -1)^2}{\sec ^2 θ-1}} + \sqrt{\dfrac{(\sec θ +1)^2}{\sec ^2 θ -1}}$

$\dfrac{\sec θ -1}{\tan θ} + \dfrac{\sec θ +1}{\tan θ}$

$\dfrac{\sec θ -1+ \sec θ +1}{\tan θ}$

$\dfrac{2 \sec θ }{\tan θ}$

$\rm \implies 2 \cosec θ$