Question

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Answer 1

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ii) Let the number be x.

$\frac{1}{4}x \: - 7 = 5$

$= > \frac{1}{4} x \: = 5 + 7$

$= > \frac{1}{4}x \: = 12$

$= > x \: = 12 \times 4$

$= > x \: = 48$

iii) We know that sum of angles of a triangles is 180°

∴ ∠A + ∠B + ∠C = 180°

But ∠A : ∠B : ∠C = 4 : 5 : 6.

Let ∠A = 4x, ∠B = 5x and ∠c = 6x,

Then 4x + 5x + 6x = 180°

⇒ 15x = 180° ⇒ x = 180°/15 = 12°

∴ ∠A = 4x = 4 × 12° = 48°

∠B = 5x = 5 × 12° = 60°

Answer 2

${\huge{\pink{↬}}} \: \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

ii) Let the number be x.

$\frac{1}{4}x \: - 7 = 5$

$= > \frac{1}{4} x \: = 5 + 7$

$= > \frac{1}{4}x \: = 12$

$= > x \: = 12 \times 4$

$= > x \: = 48$

iii) We know that sum of angles of a triangles is 180°

∴ ∠A + ∠B + ∠C = 180°

But ∠A : ∠B : ∠C = 4 : 5 : 6.

Let ∠A = 4x, ∠B = 5x and ∠c = 6x,

Then 4x + 5x + 6x = 180°

⇒ 15x = 180° ⇒ x = 180°/15 = 12°

∴ ∠A = 4x = 4 × 12° = 48°

∠B = 5x = 5 × 12° = 60°