Kinetic energy of electron = 120 eV
De Broglie wavelength ???
Answers
Explanation:
As, p= root2m K. M
= 2×9×10 ^−31 ×120×1.6×10 ^−19
=5.88×10^ −24 kgms ^−1
de Broglie wavelength,
λ= h/p
= 5.88×10 ^−24\ 6.63×10 ^−34
=1.13×10−10m=1.13A°
Answer:
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