Chemistry, asked by shahinasalam21, 3 months ago

Kinetic energy of moving electron is 4.55× 10-25joules. 

       Calculate its wave length.

Answers

Answered by abhi473312
0

Answer:

Kinetic energy

2

1

mv

2

=4.55×10

−25

J

m=9.1×10

−31

Kg

h=6.626×10

−34

Kgm

2

s

−1

2

1

×(9.1×10

−31

)v

2

=4.55×10

25

(or)

v

2

=

9.1×10

−31

4.55×10

−25

×2

=10

6

v=10

3

msec

−1

λ=

mv

h

(9.1×10

−33

)×10

3

6.626×10

−34

=7.5×10

−7

m

λ=7.25×10

−7

m

Answered by farhaanaarif84
0

Answer:

Kinetic energy

2

1

mv

2

=4.55×10

−25

J

m=9.1×10

−31

Kg

h=6.626×10

−34

Kgm

2

s

−1

2

1

×(9.1×10

−31

)v

2

=4.55×10

25

(or)

v

2

=

9.1×10

−31

4.55×10

−25

×2

=10

6

v=10

3

msec

−1

λ=

mv

h

(9.1×10

−33

)×10

3

6.626×10

−34

=7.5×10

−7

m

λ=7.25×10

−7

m

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