Kinetic energy of moving electron is 4.55× 10-25joules.
Calculate its wave length.
Answers
Answered by
0
Answer:
Kinetic energy
2
1
mv
2
=4.55×10
−25
J
m=9.1×10
−31
Kg
h=6.626×10
−34
Kgm
2
s
−1
2
1
×(9.1×10
−31
)v
2
=4.55×10
25
(or)
v
2
=
9.1×10
−31
4.55×10
−25
×2
=10
6
v=10
3
msec
−1
λ=
mv
h
(9.1×10
−33
)×10
3
6.626×10
−34
=7.5×10
−7
m
λ=7.25×10
−7
m
Answered by
0
Answer:
Kinetic energy
2
1
mv
2
=4.55×10
−25
J
m=9.1×10
−31
Kg
h=6.626×10
−34
Kgm
2
s
−1
2
1
×(9.1×10
−31
)v
2
=4.55×10
25
(or)
v
2
=
9.1×10
−31
4.55×10
−25
×2
=10
6
v=10
3
msec
−1
λ=
mv
h
(9.1×10
−33
)×10
3
6.626×10
−34
=7.5×10
−7
m
λ=7.25×10
−7
m
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