kirshna lend 10000 to gopal and radha for 2yrs .gopal agrees to pay simple intrest at 12% p.a and radha agrees to pay compound intrest at the rate of 9% p.a .if radha paid rs 596.70 more than gopal as the intrest ,find how much did krishna lend to each other?
Answers
Step-by-step explanation:
Let a be any positive integer and b=4, then by Euclid's algorithm,
a=4q+r, for some integer q≥0 and r=0,1,2,3
So, a=4q or 4q+1 or 4q+2 or 4q+3 because 0≤r<4.
Now, 4q that is (2×2q) is an even number.
Therefore, 4q+1 is an odd number.
Now, 4q+2 that is 2(2q+1) which is also an even number.
Therefore, (4q+2)+1=4q+3 is an odd number.
Hence, we can say that any even integer can be written in the form of 4q or 4q+2 where q is a whole number
Answer:
Gopal (p) = Rs 3000
Radha (p) = Rs 7000
Step-by-step explanation:
let money lent Goapal (p) = x.
time (T) = 2years
Rate (R) = 12%
simple interest = ?
we know,,
for Gopal
simpl interest = PTR \100
= x ×2×12/100
= 24x\100
= 0.24x
and Radha ( p) = 10000 -
Time (T) =2
Rate (R) = 9%
compound interest == ?
for Radha
c.i. = p[(1+R\100) ^T-1]
= 10000-x [ (1 +9\100) ^2-1]
= 10000-x [(1.09) ^2-1]
= 10000 - x [1.1881-1]
= 10000 - x [0.1881]
=1,881 - 0.1881x
According equation
The difference c. I. - s. I = Rs.596.70
1881 - 0.1881x - 0.24x = 596.70
1881-596.70 = 0.4281x
X == 1284.3\ 0.4281
;. x = Rs. 3000
Now,
Gopal lent money (p) = Rs. 3000
and Radha lent money (p) = 10000 - 3000
= Rs. 7000