Question

KM is a straight line of 13 units. If K has the co-ordinates (2,5) and M has the coordinates (x ,-7), find the possible values of x.

Answer 1

Given:

K (2, 5)

M (x, -7)

To find:

Value of x

Solution:

1) It is given in the question that the length of KM is 13 unit.

2)  So by the distance formula

$\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

• $\sqrt{(x-2)^{2}+(-7-5)^{2}}$ = 13

• $(x-2)^{2} + (-12)^{2}$ = 169

• x²+4-4x+144 = 169

• x²-4x = 169-148

• x²-4x = 21

• x²-4x-21 = 0

• x²-7x+3x-21=0

• x(x-7)+3(x-7)=0

• (x-7)(x+3)=0

• x = 7 and x = -3

Values of x are 7 and -3

Answer 2

Answer:

Here is your Answer Here X would be either 7 or -3