Chemistry, asked by ChetansMehra2504, 1 year ago

What happens when 1-bromopropane is heated with alcoholic caustic potash?

Answers

Answered by rakeshmohata
34
When 1 bromopropane is heated with alcoholic KOH, the bromine with the alpha H (hydrogen from the carbon beside the carbon bonded with functional group) is removed and thus.. Forms 1 propene.
Ch3Ch2Ch2Br ---AL. KOH--> Ch3Ch=Ch2
Answered by hotelcalifornia
2

When 1-bromopropane is heated with alcoholic caustic potash, propene is formed.

How does a reaction take place?

  • At the point when 1 bromopropane is warmed with alcoholic KOH, the bromine with the alpha H (hydrogen from the carbon alongside the carbon fortified with useful gathering) is eliminated and subsequently forms 1 propene.
  • A solid base is given i.e alcoholic potash, subsequently, this is an Electrophilic reaction.
  • Alcoholic potash (KOH) is a dehydrohalogenation specialist; it responds with an alkyl halide and alkene structures as a result.

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