Question

koi bhi ek question solve kar do​

Answer 1

Answer:

Step-by-step explanation:

Q.32 - 2nd Part

Let one no.be x and second number be y

x+y = 15 ----eqn1

Reciprocal of x & y = 1/x,1/y

1/x+1/y = 3/10 ----eqn2

From 1

x = 15-y ---- eqn3

Putting the value of eqn3 in eqn2

1/15-y + 1/y = 3/10

y+15-y/(15-y)*y = 3/10

10 * 15 = 3*(15y-y^2)

150/3 = (15y-y^2)

y^2-15y+50=0

y^2-10y-5y+50 = 0

y(y-10)-5(y-10)

(y-5)(y-10)

y = 5,10

x = 15-y = 15- 5or10 = 10 or 5

x and y  = 5,10