Question

koi bta do pls pls those who anwer this question they will get on mackbook
I am not saying lie pls bta do. ​

Answer 1

${\huge{\sf{\red{\frak{\underline{Answer :-}}}}}}$

Case (1) :-

$\mapsto \sf \: \frac{x - 5}{4} = \frac{x - 3}{5}$

[ Cross multiplication : We get : ]

$\mapsto \sf \: 5(x - 5) = 4(x - 3)$

$\mapsto \sf \: 5x - 25 = 4x - 12$

$\mapsto \sf \: 5x - 4x = - 12 + 25$

$\mapsto { \red{ \boxed{ \sf{x = 13}}}}$

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Case (2) :-

$\mapsto \sf \: \frac{8x - 3}{3x} = 2$

$\mapsto \sf \: 8x - 3 = 3x \times 2$

$\mapsto \sf \: 8x - 3 = 6x$

$\mapsto \sf \: 8x - 6x = 3$

$\mapsto \: \sf \: 2x = 3$

$\mapsto{ \blue{\boxed{ \sf{ x = \frac{3}{2} }}}}$

Answer 2

Solution :

(c)

$: \implies \sf \dfrac{x-5}{4} = \dfrac{x - 3}{5} \: \: \: \: \: \bigg \lgroup \bf Given \bigg \rgroup$

$: \implies \sf (x - 5)5 = 4(x - 3)\: \: \: \: \: \Bigg \lgroup \bf By \: cross \: multipliying \Bigg \rgroup$

$: \implies \sf 5x - 25= 4x - 12$

$: \implies \sf 5x - 4x = - 12 + 25$

$: \implies\underline{ \boxed{\textsf{ \textbf{x = 13}}}}$

__________________....

(f)

$\dashrightarrow\:\:\sf \dfrac{8x - 3}{3x} = 2\: \: \: \: \: \bigg \lgroup \bf Given \bigg \rgroup$

$\dashrightarrow\:\:\sf 8x - 3 = 2(3x)$

$\dashrightarrow\:\:\sf 8x - 3 = 6x$

$\dashrightarrow\:\:\sf 8x - 6x = 3$

$\dashrightarrow\:\:\sf 2x = 3$

$\dashrightarrow \: \: \underline{ \boxed{\textsf{ \textbf{x = \dfrac{3}{2} }}}}$