Math, asked by victoriaqueen, 10 months ago

koi solve kardo mai sada uski aabhari rahungi​

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Answered by Anonymous
3

refer Attachment

(cd)³ × (c²d) = c² d

 \tt { (\frac{2x^4}{y}) }^{5}   \div   { (\frac{ </strong><strong>-</strong><strong> 4x}{y^2} )}^{3}  =   </strong><strong>-</strong><strong>\frac{  x ^{17} \: y}{2}

(p²q) × (p³q) = (pq)²

 {( \frac{3a ^5}{b ^3}) }^{4}  \div  { (\frac{ - 9a ^3}{b ^6} )}^{2}  =   {a}^{14}

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