Math, asked by Eshitaa, 1 year ago

Krishan bought oranges at 50 rupees. He had to sell them at a loss of 4/100. Find the selling price of one orange.

Answers

Answered by shetriyas
8
Kishin bought oranges at Rs. 50 per dozenso,CP(Cost Price) = Rs. 50loss % = 4SP(Selling Price) = 48 because 100 - 4 = Rs. 96                                     and its half is 50.So, half of 4 is 2 and 50 - 2 = Rs. 48 and 48 / 12 = rs.4 is the rate of 1 orange when selling.
If you ask where did 12 come then 1 dozen = 12 oranges and you said to say the rate of 1 orange.
There are two ways to find
Answered by rajaniprasad315
2

Answer:

Step-by-step explanation:

Kishin bought oranges at Rs. 50 per dozenso,CP(Cost Price) = Rs. 50loss % = 4SP(Selling Price) = 48 because 100 - 4 = Rs. 96                                     and its half is 50.So, half of 4 is 2 and 50 - 2 = Rs. 48 and 48 / 12 = rs.4 is the rate of 1 orange when selling.

If you ask where did 12 come then 1 dozen = 12 oranges and you said to say the rate of 1 orange.

There are two ways to find

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