Kumud read 6/11th of a book in 1 st week and 3/8th of the remaining book in 2nd week. if there were 175 pages unread after 2nd week, how many pages were there in the book
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Given :- Kumud read 6/11 th of a book in 1 st week and 3/8th of the remaining book in 2nd week. If there were 175 pages unread after 2nd week, how many pages were there in the book ?
Solution :-
Let us assume that, there were x pages in the book .
given that,
→ in first week kumud read = (6/11)th of total pages = (6/11) * x = (6x/11)
then,
→ pages left after one week = x - (6x/11) = (5x/11) pages .
now, given that,
→ in second week he read = (3/8)th of the remaining = (3/8) of (5x/11) = (15x/88) pages .
then,
→ pages left after second week = (5x/11) - (15x/88) = (40x - 15x)/88 = (25x/88) pages .
therefore,
→ (25x/88) = 175 pages .
→ x = (175 * 88)/25
→ x = 616 pages . (Ans.)
Hence, there were 616 pages in the book .
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