Question

Kushal's age is three times the sum of the ages of his two sons. 5 years hence, his age will be double the sum of their ages. Find kushal's present age.

Answer 1

Answer:

45

Step-by-step explanation:

X, Y ,Z are ages of kushal and his sons

given X= 3(Y+Z) then     Y+Z =X/3

 after five years  X+5 =2(Y+5+Z+5)

                            X+5 =2(Y+Z) +2(10)

                            X =2(Y+Z) +20 -5

                           X =2X/3 +15      

                           x-2x/3 =15

                           (3X -2X)/3 =15

                             X/3=15

                                 X=45

VERIFICATION

                  now his age 45  ,sum of sons ages 15

               after 5 years    his age 50 ,sum of sons ages 25

Answer 2

$\huge\sf\underline{\pink{An}\purple{sW}\green{eR}}$

Present age of man is 45 years.

Given :-

The age of a man is three times the sum of the ages of his two sons.

5 years hence, his age will be double the sum of their ages.

To find :-

Present age of man.

Solution :-

Let ,

Man's present age = x years

Present age of 1st son = y years

Present age of 2nd son = z years

$\red{\underline{\sf{According\:to\:the\:1st\: condition:-}}}$

The age of a man is three times the sum of the ages of his two sons.

➪ x = 3(y+z)

➪ y+z = x/3 ..................(i)

$\red{\underline{\sf{According\:to\:the\:2nd\: condition:-}}}$

5 years hence, his age will be double the sum of their ages

5 years hence,

Man's age = (x+5) years

Age of 1st son = (y+5) years

Age of 2nd son = (z+5) years

➪ x+5 = 2[(y+5)+(z+5)]

➪ x+5 = 2(y+z+10)

[ put y+z = x/3 from eq (i)]

➪ x+5 = 2(x/3 + 10)

➪ x+5 = 2x/3 + 20

➪ x - 2x/3 = 20-5

➪ x/3 = 15

➪ x = 45

† Present age of man is 45 years.

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