Question

kx+3y=1 and 12x+ky=2 find the value of k
pls explain it

Answer 1

Answer:

The given equations are,

kx + 3y = 1

12x + ky = 2

To find:

Value of “k”

Solution:

The above equation can also be written as,

kx + 3y - 1 = 0

12x + ky - 2 = 0

Here, for this equations,

a₁ = k, b₁ = 3, c₁ = -1

a₂ = 12, b₂ = k, c₂ = -2

For this set of equations,

☆ There is no solutions ☆

So to Find the value of k,

We have to use the formula of

“no solution”

The formula is,

$\boxed{a1/a2 = b1/b2 ≠ c1/c2}$

So,

k/12 = 3/k ≠ -1/-2

∴ 3/k ≠ 1/2

⇒ k ≠ 6

Hence, $\boxed { k = -6 }$

Answer 2

Answer:

Kx + 3y=1

12x+ ky= 2

a1/a2 = k/12

b1/b2 = 3/k

c1/c2 = 1/2

these equations has no solution. So

k 3 1

_ = _ not = _

12 k 2

2k = 12×3

2k=36

k=36÷2

k=18

Hope it helps you

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