Question

kx+3y-( k-3)=0
12x+ky-k=0
Will have infinite solution

Answer 1

$\mathfrak{your \: answer}$

For infinite many solutions=

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

a1=k. b1=3. c1=-k+3
a2=12. b2=k. c2=-k
I. II. III.
TAKING I & II
We get,

$\frac{a1}{a2} = \frac{b1}{b2}$

$\frac{k}{12} = \frac{3}{k}$

${k}^{2} = 12 \times 3$

${k}^{2} = 36$

$k = \sqrt{36}$

$k = 6$

Putting the value of k

$\frac{6}{12} = \frac{3}{6} = \frac{ - 6 + 3}{ - 6}$

$\frac{1}{2} = \frac{1}{2} = \frac{1}{2}$

$\huge \boxed{hence \: proved}$

Answer 2

HOPE IT HELPS YOU

PLZZ MARK BRAINLIEST