Question

kx(x-2)+6=0 find the value of k​

Answer 1

Answer:

Given kx(x – 2) + 6 = 0

kx2 – 2kx + 6 = 0

Since the given quadratic equation has equal roots we have b2 – 4ac = 0

That is (– 2k)2 – 4(k)(6) = 0

⇒ 4k2 – 24k = 0

⇒ 4k(k – 6) = 0

⇒ 4k = 0 or (k – 6) = 0

∴ k = 0 or 6

Answer 2

kx^2-2kx=-6

kx^2 =-6+2kx

k=-6+2kx/x^2