Question

kx+y=k2and1x+ky=1 have infinietly many solutions

Answer 1

K/1=1/K=K2/1 it means K=1,-1

Answer 2

a1 / a2 = b1 / b2 not = c1 / c2

therefor we get a1 / a2 = b1 / b2 ; k = 1 / k

k[sq] = 1

k = 1

for unique solutions

 a1 / a2 not = b1 / b2

k / 1 not = 1 / k

k[sq] not  = 1 

k not = 1.