Question

Kyle throws a baseball straight up from a height of 4 feet with an initial speed of 30 feet per second. What is the maximum height of the baseball?

Answer 1

Answer:

applying formulas directly we can get the answer

Answer 2

The maximum height of the baseball

= 17.97 feet.

Given:

Kyle throws a baseball straight up from a height of 4 feet with an initial speed of 30 feet per second.

To find:

The maximum height of the baseball.

Formula used:

V = u+at

S = ut + $\frac{1}{2}$ ×  at ²

Where u = Initial velocity

t = time

a = Acceleration of body  

s = Total distance moved.

Explanation:

• Kyle throws a baseball straight up Against the acceleration due to gravity
• Acceleration due to gravity = 9.81 m/s²
• The base ball throw opposite to Acceleration due to gravity so
• Acceleration due to gravity = - 9.81 m/s²
• After attending maximum height the velocity of baseball = 0 m/s
• Initial velocity of baseball = 30 feet per sec
• 1 feet per sec = 0.3048 meter per sec

• 30 feet per sec = 0.3048×30 meter per sec

                                  = 9.144 m/s

• So Initial velocity of baseball = 9.144 m/s

                 V = u+at  

                 0 = 9.144 - 9.81 × t

              9.81 × t = 9.144

                   t = 0.932 sec

• We can use 2nd equation

             s = ut + $\frac{1}{2}$ ×  at ²

             s = 9.144×0.932 + $\frac{1}{2}$ ×  (-9.81) × 0.932²

             s = 4.26 meter.

     1 meter =  3.28 feet

• 4.26 meter = 13.97 feet
• But initial height =  4 feet
• Hence Total height = 13.97 +4

                                         = 17.97 feet.

• The maximum height of the baseball = 17.97 feet.

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