Question

l^2- 52l+ 640 =0
plz solve this quadratic equation​

Answer 1

Answer:

I= -20 or -32

Hope it helps and sorry about handwriting

Answer 2

Answer:

I²-52I+640=0

I²+(-32-20)I+(-32)×(-20)=0

(I-32)(I-20)=0

Maybe,

I-32=0

I=32(Ans.)

Or,

I-20=0

I=20(Ans. )

Step-by-step explanation:

Theory :-

We know that, (x+a) ×(x+b) =x²+(a+b) x+ab [a, b are constant]

Conclusion :-

So, we can say the constant is the multiplication

of two factors and the sum of those two factor(Beware from + - problem).

process :-

I find out all factors firstly. And tries to find out two numbers by which I can form this equation without breaking any rule. By observing or examining the factors. I find out '- 32' and '- 20' are the lucky pair maintaining the argument.

"{Odd+Odd=Even, Odd+Even=Odd,

Even+Even=Even, Even × Even=Even,

Even × Odd=Even, Odd × Odd=Odd, (+a) (-b)= -ab,

(-a) (-b)= ab , (a) ×(b)=ab }", You should consider this logics too.