l^2- 52l+ 640 =0
plz solve this quadratic equation
Answers
Answer:
I= -20 or -32
Hope it helps and sorry about handwriting

Answer:
I²-52I+640=0
I²+(-32-20)I+(-32)×(-20)=0
(I-32)(I-20)=0
Maybe,
I-32=0
I=32(Ans.)
Or,
I-20=0
I=20(Ans. )
Step-by-step explanation:
Theory :-
We know that, (x+a) ×(x+b) =x²+(a+b) x+ab [a, b are constant]
Conclusion :-
So, we can say the constant is the multiplication
of two factors and the sum of those two factor(Beware from + - problem).
process :-
I find out all factors firstly. And tries to find out two numbers by which I can form this equation without breaking any rule. By observing or examining the factors. I find out '- 32' and '- 20' are the lucky pair maintaining the argument.
"{Odd+Odd=Even, Odd+Even=Odd,
Even+Even=Even, Even × Even=Even,
Even × Odd=Even, Odd × Odd=Odd, (+a) (-b)= -ab,
(-a) (-b)= ab , (a) ×(b)=ab }", You should consider this logics too.