Question

L and B are zeroes of Quarratic Polynomial
2 -5x +6. Find the value of 1/L+1/B-LB​

Answer 1

Answer:

addition of root of quadrtic equation is equal to the -coefficient of x divide by coefficient of x^2

product of roots equal to constant term divide by coefficient of x^2

so

l+b=5/2  lb=3

1/l+1/b-lb

(l+b)/lb-lb

(5/2)/3-3

-13/6

thank you

Answer 2

Answer:

Step-by-step explanation:

x² -5x +6

L and B are zeros

then L+B=5,LB=6/1=6

--------------------------------

Hence

1/L+1/B-LB

=1/LB( L+B-L²B²)

=1/6(5-6²)

=1/6(5-36)

=1/6*(31)

=-31/6