Math, asked by Su2020, 8 months ago

l and m are two parallel lines intersected by another pair of parallel lines p and q. show that triangle abc ≅ triangle cda by sss congruence. Please answer it. Will surely mark correct answer as Brainliest. ​

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Answered by 000000000080
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hajarafatima

26.11.2017

Math

Secondary School

+5 pts

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l and m are two parallel lines intersected by another pair of parallel lines p and q show that triangle ABC is congruent to triangle CDA

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Tuktuki3

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the two parallel lines I and M are bisecting the pair of P and Q , by forming a vertical point or angle. We have to prove that the triangle ABC is similiar to CDA.

ABC=CDA

by taking the measurement of the angle of triangle ABC, we found that it's measure is(anything as suppose) 60°. Now we take the measurement of CBA= 60° itself.

so, ABC=60°, CBA=60°

=ABC=CBA as their measurement is clear to be the same

[proved]

Answered by ItzDeadDeal
3

Answer:

GiVeN

l and m are two parallel lines intersected by another pair of parallel lines p and q. show that triangle abc ≅ triangle cda by sss congruence.

In ΔABC and ΔCDA,

SoLuTiON

∠BAC = ∠DCA (Alternate interior angles, as p || q)

AC = CA (Common)

∠BCA = ∠DAC (Alternate interior angles, as l || m)

∴ ΔABC ≅ ΔCDA (By ASA congruence rule)

  \sf \red{Hence \:  we  \: are \:  done !!}

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